Solve this equation. x^3 - 4x^2 + 6x - 24 = 0

To solve the equation x ^ 3 - 4 x ^ 2 + 6 x - 2 4 = 0 , we can use the quadr atic formula : \n \n x = (- b ± sq rt ( b ^ 2 - 4 ac )) / 2 a \n \n where a = 1 , b = - 4 , and c = 6 . \n \n Sub st itut ing these values into the formula , we get : \n \n x = (- (- 4 ) ± sq rt (( - 4 )^ 2 - 4 ( 1 )( 6 ))) / 2 ( 1 ) \n \n Sim pl ifying , we get : \n \n x = ( 4 ± sq rt ( 1 6 - 2 4 )) / 2 \n \n x = ( 4 ± sq rt (- 8 )) / 2 \n \n x = ( 4 ± 2 i ) / 2 \n \n There fore , the solutions to the equation are : \n \n x = ( 4 + 2 i ) / 2 = 3 i \n \n x = ( 4 - 2 i ) / 2 = 1 </s>