Write a program to find the nth Fibonacci number using dynamic programming.

Sure , I ' d be happy to help you with that ! Here ' s a Python program that uses dynamic programming to find the n th F ib on acci number : \n `` ` python \n def fib on acci ( n ): \n if n <= 1 : \n return n \n else : \n return fib on acci ( n - 1 ) + fib on acci ( n - 2 ) \n `` ` \n This program works by recurs ively calling itself with smaller and smaller values of ` n `, until it reaches the base cases of ` n = 0 ` or ` n = 1 `, at which point it returns ` n ` itself . For larger values of ` n `, it returns the sum of the previous two F ib on acci numbers , which it calcul ates using recurs ion . \n To use this program , simply call the ` f ib on acci ` function with the desired value of ` n `, like this : \n `` ` python \n fib on acci ( 1 0 ) \n 5 5 \n `` ` \n I hope this helps ! Let me know if you have any questions . </s>