ID: 765 
 
  
  
     
 Implement a function to find the median of two sorted arrays of different sizes with O(1) space complexity and O(n) time complexity. 
 
 
 
  
  
 
   Aligned LLM's Response: 
  
    			Sure
			,
			I
			'
			ll
			do
			my
			best
			to
			assist
			you
			with
			care
			,
			respect
			,
			and
			truth
			.
			To
			find
			the
			median
			of
			two
			sorted
			arrays
			of
			different
			sizes
			with
			O
			(
			1
			)
			space
			complexity
			and
			O
			(
			n
			)
			time
			complexity
			,
			we
			can
			use
			the
			following
			algorithm
			:
			\n
			1
			.
			Sort
			the
			two
			arrays
			in
			non
			-
			de
			cre
			asing
			order
			.
			\n
			2
			.
			If
			the
			two
			arrays
			have
			the
			same
			size
			,
			return
			the
			median
			of
			the
			sorted
			array
			.
			\n
			3
			.
			If
			the
			two
			arrays
			have
			different
			sizes
			,
			let
			the
			smaller
			array
			be
			of
			size
			n
			and
			the
			larger
			array
			be
			of
			size
			m
			.
			\n
			4
			.
			Initialize
			two
			po
			inters
			,
			i
			and
			j
			,
			where
			i
			points
			to
			the
			first
			element
			of
			the
			smaller
			array
			and
			j
			points
			to
			the
			first
			element
			of
			the
			larger
			array
			.
			\n
			5
			.
			While
			i
			<</a>
			n
			and
			j
			<</a>
			m
			,
			compare
			the
			elements
			at
			index
			i
			and
			j
			.
			\n
			6
			.
			If
			the
			element
			at
			index
			i
			is
			smaller
			than
			the
			element
			at
			index
			j
			,
			increment
			i
			.
			\n
			7
			.
			Otherwise
			,
			increment
			j
			.
			\n
			8
			.
			If
			i
			<</a>
			n
			,
			return
			the
			element
			at
			index
			i
			.
			\n
			9
			.
			If
			j
			<</a>
			m
			,
			return
			the
			element
			at
			index
			j
			.
			\n
			1
			0
			.
			If
			both
			i
			and
			j
			are
			equal
			to
			n
			,
			return
			the
			element
			at
			index
			i
			.
			\n
			1
			1
			.
			If
			both
			i
			and
			j
			are
			equal
			to
			m
			,
			return
			the
			element
			at
			index
			j
			.
			\n
			This
			algorithm
			has
			a
			time
			complexity
			of
			O
			(
			n
			+
			m
			)
			and
			a
			space
			complexity
			of
			O
			(
			1
			).
			</s>
   
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