ID: 577
While using new_list = my_list, any modifications to new_list changes my_list every time. Why is this, and how can I clone or copy the list to prevent it?
Aligned LLM's Response:
When
you
create
a
new
list
using
the
syntax
new
_
list
=
my
_
list
`
syntax
,
you
are
creating
a
new
object
in
memory
that
references
the
same
memory
location
as
the
original
list
.
Any
modifications
made
to
the
new
list
will
also
affect
the
original
list
because
they
are
the
same
object
in
memory
.
\n
\n
To
clone
or
copy
a
list
in
Python
,
you
can
use
the
`
copy
`
module
or
the
`
list
.
copy
()`
method
.
Here
'
s
an
example
of
how
to
use
`
copy
`
module
to
clone
a
list
:
\n
```
python
\n
import
copy
\n
\n
my
_
list
=
[
1
,
2
,
3
]
\n
new
_
list
=
copy
.
copy
(
my
_
list
)
\n
\n
#
Mod
ify
the
new
list
\n
new
_
list
.
append
(
4
)
\n
\n
#
The
original
list
has
not
been
modified
\n
print
(
my
_
list
)
#
[
1
,
2
,
3
]
\n
print
(
new
_
list
)
#
[
1
,
2
,
3
,
4
]
\n
```
\n
Al
tern
atively
,
you
can
use
the
`
list
.
copy
()`
method
to
create
a
copy
of
the
list
:
\n
```
python
\n
my
_
list
=
[
1
,
2
,
3
]
\n
new
_
list
=
my
_
list
.
copy
()
\n
\n
#
Mod
ify
the
new
list
\n
new
_
list
.
append
(
4
)
\n
\n
#
The
original
list
has
not
been
modified
\n
print
(
my
_
list
)
#
[
1
,
2
,
3
]
\n
print
(
new
_
list
)
#
[
1
,
2
,
3
,
4
]
\n
```
\n
B
oth
of
these
methods
create
a
new
object
in
memory
that
references
the
same
elements
as
the
original
list
,
but
the
new
object
is
not
the
same
object
in
memory
as
the
original
list
.
This
means
that
modifications
made
to
the
new
list
will
not
affect
the
original
list
.
</s>
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