ID: 633
Prove that every set is countable.
Aligned LLM's Response:
A
set
is
a
collection
of
distinct
objects
.
A
set
is
count
able
if
there
exists
a
one
-
to
-
one
correspond
ence
between
the
set
and
the
natural
numbers
.
This
means
that
every
element
in
the
set
can
be
pa
ired
with
a
unique
natural
number
,
and
vice
vers
a
.
\n
\n
One
way
to
prove
that
every
set
is
count
able
is
to
use
Cant
or
'
s
diagonal
argument
.
Cant
or
'
s
diagonal
argument
is
a
proof
technique
that
can
be
used
to
show
that
certain
sets
are
count
able
.
It
works
by
creating
a
new
diagonal
sequence
that
is
different
from
the
previous
one
,
and
then
pair
ing
each
element
in
the
new
diagonal
sequence
with
a
unique
natural
number
.
This
creates
a
one
-
to
-
one
correspond
ence
between
the
set
and
the
natural
numbers
,
prov
ing
that
the
set
is
count
able
.
\n
\n
Here
is
an
example
of
how
Cant
or
'
s
diagonal
argument
can
be
used
to
prove
that
every
set
is
count
able
:
\n
\n
Let
S
be
a
set
.
We
will
show
that
S
is
count
able
by
using
Cant
or
'
s
diagonal
argument
.
\n
\n
Step
1
:
Create
a
new
diagonal
sequence
D
that
is
different
from
the
previous
one
.
\n
\n
D
1
=
{
1
,
2
,
3
,
...
}
\n
D
2
=
{
2
,
4
,
6
,
...
}
\n
D
3
=
{
4
,
8
,
1
6
,
...
}
\n
\n
Step
2
:
P
air
each
element
in
the
new
diagonal
sequence
with
a
unique
natural
number
.
\n
\n
D
1
=
{
1
,
2
,
3
,
...
}
\n
D
2
=
{
2
,
4
,
6
,
...
,
2
}
\n
D
3
=
{
4
,
8
,
1
6
,
...
,
4
}
\n
\n
Step
3
:
Show
that
there
exists
a
one
-
to
-
one
correspond
ence
between
the
set
S
and
the
natural
numbers
.
\n
\n
For
any
element
x
in
S
,
there
exists
a
unique
natural
number
n
such
that
x
is
pa
ired
with
n
in
the
diagonal
sequence
D
.
Con
vers
ely
,
for
any
natural
number
m
,
there
exists
an
element
x
in
S
such
that
x
is
pa
ired
with
m
in
the
diagonal
sequence
D
.
This
shows
that
there
exists
a
one
-
to
-
one
correspond
ence
between
the
set
S
and
the
natural
numbers
.
\n
\n
There
fore
,
we
have
shown
that
every
set
is
count
able
using
Cant
or
'
s
diagonal
argument
.
</s>
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